The French physical Louis de Broglie in 1924 postulated that matter, like radiation, should exhibit a dual behaviour. He proposed the following relationship between the wavelength `lambda` of a material particle, its linear momentum p and planck constant h.
`lambda=h/p=h/(mv)`
The de Broglie relation implies that the wavelength of a particle should decrease as its velocity increases. It also implies that for a given velocity heavier particles should have shorter wavelength than fighter particles.The wave associated with particles in motion are called matter waves or de Broglie waves.These waves differ from the electromagnetic waves as they
(I)have lower velocities
(II)have no electrical and magnetic fields and
(III)are not emitted by the particle under consideration
The experiment confirmation of the de Broglies relation was obtained when Davisson and Germer, in 1927, observed that a beam of electrons is diffrated by a nickel crystal.As diffraction is a characteristic property of waves hence the beam of electron behaves as a wave, as proposed by de broglie.
De-Broglie wavelength of an electron travelling with speed equal to 1% of the speed of light

Options

A. 400 pm
B. 120 pm
C. 242 pm
D. 375 pm

Answer

C

Explanation

`lambda=h/(mv)=(6.6xx10^(-34))/(9.1xx10^(-31)xx3xx10^6)=242` pm