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The electron gain enthalpies of halogens...

The electron gain enthalpies of halogens are as given below:
`F =- 332, CI =- 349, Br =- 324, I =- 295 kJ mol^(-1)`. The less negative value for F as compared to that of CI is due to:

A

Strong electron-electron repulsions in the compact 2p-sub shell of F

B

Weak electron-electron repulsions in the bigger 3p-sub shell of Cl

C

Smaller electronegativity value of F than Cl

D

(A) & (B) both

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The correct Answer is:
D

Due to small size of F atom, the electron-electron repulsions in compact 2-p shell are large and hence the incoming electron is not accepted with the same ease as is the case with Cl (less electron-electron repulsion)
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The amount of energy released when an electron is added to an isolated gaseous atom to produce a monovalent anion is called electron affinity of first electron affinity or electron gain enthalpy. The first electron affinity is given a negative sign as the addition of an electron to a neutral atom is an exoergic process. The addition of electron to A^(-) requires energy to overcome the force of repulsion. Thus, the second electron affinity is an endoergic process. The magnitude of electron affinity depends on a number of factors such as (i) atomic size (ii) effective nuclear charge (iii) screening effects (iv) half and fully filled orbitals and (v) shape of orbital. In general, electron affinity increase as the atomic radii decrease in a period. However, there are exceptions when the atoms have stable configuration. In a group, electron affinity decreases as the size increases. However, the members of 3rd period have somewhat higher values than the members in the 2nd period of the same subgroups. The electron affinities of halogens are: F =- 332, CI =- 349, Br =- 324,I =- 295 kJ mol^(-1) The higher value of CI as compared to that of F^(-) is due to:

The electron affinities of halogens are F=322, Cl=349,Be=324,I=295kJ mol^(-1) . The higher value for Cl as compared to that of F is due to

Few values of enthalpies are given below: O=-141 KJ mol^(-1) F= -328 KJ mol^(-1) S= -200 KJ mol^(-1) Cl= -349 KJ mol^(-1) What do these values show?

The electron gain enthalpy values (in kJ mol^(-1) ) of three halogens, X, Y and Z are respectively -349, -333 and -325. Then X, Y and Z are respectively

Correct order of electron gain enthalpy (Kj/mole) of F, Cl, Br, I

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