In which of the following sets the central atom of each member involves `sp^3` hybridisation ?

Options

A. `IO_4^(-),I Cl_4^(-),IF_4^(+)`
B. `XeO_3, XeO_4, XeF_4`
C. `SO_3, SO_3^(2-),SO_4^(2-)`
D. `PCl_4^(+),BF_4^(-),CIO_4^(-)`

Answer

D

Explanation

Hybridisation is calculated by steric number rule.
Steric no =no of atoms attached to central atom + no of lone pairs present on central atom.
Steric no for `IO_4^(-)=4+0=4 " " sp^3` , Steric no for `IC l_4^(-)`=4+2=6 `" "sp^3d^2`
Steric no for `IF_4^(+)`=4+1=5 `sp^3d`, Steric no for `SO_3`3+0=3 `" "sp^2`
Steric no for `PCl_4^(+)`=4+0=4 `sp^3` , Steric no for `BF_4^-` =4+0=4 `sp^3`
Steric no for `XeO_3`=3+1=4 `sp^3` , Steric no for `XeO_4`=4+0=4 `sp^3`Steric no for `XeF_4`=4+2=6 `sp^3d^2`, Steric no for `CIO_4^-` =4+0=4 `sp^3`