Consider the following statements and arrange in the order of the true/false as given in the codes.
`S_1`:Both `[Co(o x )_3]^(3-)` and `[CoF_6]^(3-)` are paramagnetic.
`S_2`:`CoCl_(3)3NH_3` complex is non-conducting.
`S_3`:The number of possible isomers for the complex `[Pt(NO_2)(py) (OH)(NH_3)]` is six.
`S_4`:The oxidation state of iron in brown ring complex `[Fe(H_2O)_5NO^+`] `SO_4` is + || Where NO is `NO^(+)`

Options

A. F T T F
B. T T T T
C. F T T F
D. T T T F

Answer

C

Explanation

`S_1`:`[CoF_6]^(3-)` is paramagnetic with 5 unpaired electrons but `[Co(o x)_3]^(3-)` is diamagnetic as all electrons are paired
`S_2`:It exists as `[Co(NH_3)_3Cl_3]`, neutral molecule
`S_3`:It is correct statement . It shows linkage and geometrical isomerism.
`S_4:[Fe(+l)(H_2O)_5NO^(+)]SO_4^(2-)`