(i) A powdered substance (A) on treatment with fusion mixture gives a green coloured compound (B). (ii) The solution of (B) in boiling water on acidification with dilute `H_(2)SO_(4)` gives a pink coloured compound `(C )`.
`(iii)` The aqueous solution of (A) on treatment with NaOH and `Br_(2)-` water gives a compound (D).
(iv) A solution of (D) in conc. `HNO_(3)` on treatment with lead peroxide at boiling temperature produced a compound (E) which was of the same coloure at that of (C).
(v) A solution of (A) on treatment with a solution of barium chloride gave a white precipitate of compound (F) Which was insoluble in conc. `HNO_(3)` and conc. HCl.
Which of the following is true for compound (C ).

Options

A. It oxidises ammonia to nitrogen dioxide in neutral medium
B. It is coloured and colour is due to d-d transition
C. It can be oxidised by ozone
D. It is obtained by alkaline fusion of pyrolusite in presence of air followed by electrolytic oxidation

Answer

D

Explanation

(A)`2MnO_4^(-)+2NH_3 to 2MnO_2+ N_2 + 2OH^(-)+2H_2O`
(B)`MnO_4^(-)` is pink coloured and colour is due to charge transfer.
(C )In `MnO_4^(-)` , central atom Mn is in highest oxidation state i.e. +VII and hence can not be oxidised.
(D)`MnO_2 + OH^(-)+O_2(air)overset("Fusion")toMnO_4^(2-)overset([e^-])toMnO_4^-`