A chemist opened a cupboard and found four bottles containing water solutions, each of which had lost its label.Bottles 1,2,3 contanied colourless solution, while bottle 4 contained a blue solution.The labels from the bottles were lying scattered on the floor of the cupboard.They were:
copper (II) sulphate, Hydrochloric acid
lead nitrate , Sodium carbonate
By mixing samples of the contents of the bottles, in pairs , the chemist made the following observations :
Bottle 1 +Bottle 2 `to` White precipitate is formed.
Bottle 1 +Bottle 3 `to` White precipitate is formed.
Bottle 1 +Bottle 4 `to` White precipitate is formed.
Bottle 2 +Bottle 3 `to` Colourless and odourless gas is evolved.
Bottle 2 +Bottle 4 `to` No visible reaction is observed.
Bottle 3 +Bottle 4 `to` Blue precipitate is formed.
With the help of the above observations answer the following questions.
Which of the following bottles will give white precipitate with bottle 1?

Options

A. Bottle 2
B. Bottle 3
C. Bottle 4
D. All of these

Answer

D

Explanation

`Pb^(2+)+CO_3^(2-) to PbCO_3 darr` (white)
`Pb^(2+)+2Cl^(-)toPbCl_2darr`(white)
`Pb^(2+)+SO_4^(2-)toPbSO_4 darr`(white)