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S(N)1 reaction underoges through carboca...

`S_(N)1` reaction underoges through carbocation intermediate as follows:
`R-X(aq.) overset("Slow") hArr R^(+)(aq.)+`
`X^(-) (aq.) underset ("fast") overset(H_(2)O)to ROH(aq.)+H^(+)(aq.)`
[R=t-Bu, iso-Pr, Me] `(X=Cl, Br, I)`
The correct statements are
I. The decreasing order of rate of `S_(N)1` reaction is `t-BuXgtiso-PrXgtEtXgtMeX`
II. The decreasing order of ionisation energy is `MeXgtEtXgtiso-PrXgt t-BuX`
III. The decreasing order of energy of activation is `t-BuX gt iso- PrXgtEtXgtMeX`

A

I & II are correct

B

I & III are correct

C

II and III are correct

D

I,II & III are correct

Text Solution

Verified by Experts

The correct Answer is:
A
Rate of `S_N1` reaction is a t Bu X gt iso-prXgt EtX gt MeX
So order of activation energy
t-BuXltisoPrXltEtXltMeX
order of ionisation energy
1 BuX ltiso prX lt EtX lt MeX
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