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The correct order of SN 2//E2 ratio for ...

The correct order of `S_N 2//E2` ratio for the % yield of product of the following halide is-
(P)`CH_3-CH-undersetunderset(I)(|)oversetoverset(Ph)(|)C-CH_3` , (Q)`CH_3-undersetunderset(Ph)(|)CH-undersetunderset(I)(|)CH-CH_3`
(R)`CH_3-CH_2-I` , (S)`CH_3-CH-undersetundersetI|CH-CH_3`

A

RgtSgtQgtP

B

RgtQgtSgtP

C

PgtRgtSgtQ

D

QgtPgtRgtS

Text Solution

Verified by Experts

The correct Answer is:
A
As steric hindrance increases rate of `S_(N_2)` decrease and rate of E2 increases.
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The corrent order of S_(N)2//E_(2) ratio for the % yield of product of the following halide is (P) CH_(3)-CH_(2)-underset(I)underset(|)overset(Ph)overset(|)C -CH_(3) (Q) CH_(3)-underset(Ph)underset(|)CH-underset(I)underset(|)CH -CH_(3) (R) CH_(3) -CH_(2) -I (S) CH_(3)CH_(2)-underset(I)underset(|)CH -CH_(3) .

The correct order of S_(N)2//E2 ratio for the % yield of product of the following halide is, P. CH_(3)-CH_(2)-underset(I) underset(|) overset (Ph) overset(|) (C)-CH_(3) Q. CH_(3)-underset (Ph) underset(|) (CH)-underset(I) underset(|) (CH)-CH_(3) R. CH_(3)-CH_(2)-I S. CH_(3)-CH-underset(I) underset(|) (CH)-CH_(3)

CH_3-undersetunderset(D)(|)CH-undersetunderset(CH_3)(|)CH-CH_3+Br^@ to'X' + HBr, X can be

The name of CH_3-undersetunderset(CH_3)(|)oversetoverset(CH_3)(|)C-CH_2-oversetoverset(CH_3)(|)CH-CH_3 is :

The IUPAC name of CH_(3)-undersetunderset(OH)(|)(CH)-CH_(2)-CH_(2)-CH_(2)-undersetunderset(Br)(|)oversetoverset(Br)(|)(C)-CH_(3) is:

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