The possible number of stereoisomers of the product of following reaction would be :
`Ph-CH=CH-undersetunderset(CH_3)(|)CH-CHOoverset(NH_2OH)to`

Options

A. 2
B. 4
C. 6
D. 8

Explanation

To determine the possible number of stereoisomers for the product of the given reaction, we will follow these steps:

### Step 1: Identify the Reaction
The reaction involves the compound `Ph-CH=CH(CH₃)CH-CHO` being treated with hydroxylamine (NH₂OH). The product will be an oxime formed from the carbonyl group (CHO).

### Step 2: Analyze the Structure
The starting compound has a double bond (alkene) and a carbonyl group. The presence of these functional groups suggests that we will have stereocenters in the product.

### Step 3: Identify Stereocenters
1. **Alkene (C=C)**: The double bond between the two carbon atoms allows for cis/trans (E/Z) isomerism. This gives us one stereocenter.
2. **Carbon attached to the carbonyl (C=O)**: The carbon atom bonded to the nitrogen from hydroxylamine will also serve as a stereocenter because it will have four different substituents after the reaction (Ph, CH₃, OH, and NH).
3. **The carbon adjacent to the double bond**: This carbon is also a stereocenter because it has different groups attached (Ph, CH₃, and the carbon chain).

### Step 4: Count the Stereocenters
From the analysis:
- We have identified **3 stereocenters** in the product.

### Step 5: Calculate the Number of Stereoisomers
The formula to calculate the number of stereoisomers based on the number of stereocenters (n) is given by:
\[ \text{Number of stereoisomers} = 2^n \]
Where n is the number of stereocenters.

In this case:
\[ n = 3 \]
So,
\[ \text{Number of stereoisomers} = 2^3 = 8 \]

### Conclusion
The possible number of stereoisomers of the product is **8**.