The CO in a 20L sample of gas was converted to `CO_2` by passing the gas over iodine pentoxide heated to `150^@C`:
`I_2O_5(s)+5CO(g)to5CO_2(g)+I_2(g)`
The iodine distilled at this temperature and was collected in an absorber containing 10 mL of 0.011 M `Na_2S_2O_3`.The excess hypo was back titrated with 5 mL of 0.001 M `I_2` solution.
What is the weight (in mg) of iodine produced due to the reaction with `I_2O_5(s)` when it reacted with CO(g) in 20L sample of gas ?

Options

A. 6.35 mg
B. 127 mg
C. 12.7 mg
D. 0.635 mg

Answer

C

Explanation

Weight of `I_2=0.1/2xx(2xx127)=12.7 mg`