`{:("Column-I","Column-II"),("(Analysis of Atoms)","(Characteristics)"),((A)"Total number of orbitals with m=0 in "._30 "Zn atom","(p)Number is even"),((B)"Total number of electrons with l=0 in "._12 "Mg atom","(q)Number is odd"),((C )"Maximum number of electrons with l+m=0 in "._17 "Cl atom","(r)Number is same as the number of unpaired electrons in "._25Mn^(2+)"ion"),((D)"Total number of electrons with anticlockwise spin in "._10 "Ne atom","(s)Number is greater than 5 "),(,"(t)Number is less than the number of fully filled orbitals in "._18Ar "atom"):}`

Answer

A-q,s,t ; B-p,s,t ; C-p,s ; D-q,r,t

Explanation

`._30Zn^(65)=1s^2 , 2s^2 , 2p^6 , 3s^2 , 3p^6 , 3d^10 , 4s^2`
Total number of orbitals with m=0 i.e. 1+1+1+1+1+1+1=7
`._12Mg=1s^2 , 2s^2 , 2p^6 , 3s^2`
s-orbitals have l=0 So, number of electrons =2+2+2=6
`._17Cl^(35)=1s^2 , 2s^2, 2p^6, 3s^2 3p^6`
max. no of electron with l+m=0 will be :
for s-orbitals , no of electrons =2+2+2=6
for p-orbitals , max no of electrons =2+2=4
So, max of total electrons=6+4=10
`._10Ne^20 =1s^2 , 2s^2 , 2p^6`
5 electrons will have anticlockwise spin.
Number of unpaired electron in `._25Mn^(2+)` ion=`1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^5=5`
Number of fully filled orbitals in `._18Ar` atom =`1s^2, 2s^2 , 2p^6, 3s^2 , 3p^6 =1+1+3+1+3=9`