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Find the sum of number of stereoismomers...

Find the sum of number of stereoismomers and stereocentres for the given compound.
`CH_3-CH=CH-undersetunderset(Cl)(|)CH-CH=CH-CH_3`

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Verified by Experts

The correct Answer is:
7
It is a case of symmetrical compound with 3 stereocentres & number of steroisomers =`2^(n-1)`=4
So total =7
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