A mixture contains 61.2 % BaO, 28% CaO and 10.8% (silica) impurities. What volume in mL of 3.00 M would be required to react completely with 1 g of the mixture ?

Answer

9mL

Explanation

wt. of BaO`=(1xx61.2)/100=0.612 g`
moles =`0.612/153=0.004`
wt of CaO=0.28 g
moles of CaO=`0.28/56=0.005` mol
`{:(BaO+,2HCl,toBaCl_2+H_2O),(0.004,0.004xx2,):}`
`{:(CaO+,2HCl,toCaCl_2+H_2O),(0.005,2xx0.005,):}`
number of moles of HCl required =0.008+0.01=0.018
`MV_L=0.018`
`3xxV_(mL)/1000=0.018`
V=9 ml