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All reactions are of 1st order . At ti...


All reactions are of 1st order .
At time `t=t_1(t_1gt0)`
`([B])/([C])=alpha`Therefore at
time `t=t_2` (where `t_2get_1`)
`([C])/([D])=beta`Which of the following is correct ?

A

`alpha gt beta`

B

`alpha=beta`

C

`alphabeta=0.4`

D

`alpha+beta=0.4`

Text Solution

Verified by Experts

The correct Answer is:
C
`[[B]]/[[C]]=(3k_1)/(8k_1)=3/8=alpha` (at any time)
`[[C]]/[[D]]=(8k_1)/(7.5k_2)=8/7.5=beta` (at any time)
`:. alphabeta=0.4`
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