1 g of a monobasic acid dissolved in 200 g of water lowers the freezing point by `0.186^@ C`.On the other hand when 1 g of the same acid is dissolved in water so as to make the solution 200 mL , this solution requires 125 mL of 0.1 N NaOH for complete neutralization. If `alpha` for the acid is `x xx10`.
Find x:

Answer

60

Explanation

Let molar mass of acid be m. then
0.186=`ixx1/mxx1000/200xx1.86`
Also, `1/m=125xx0.1xx10^(-3) so m=10000/125=400/5=80`
so `i=80/50=8/5=1.6=1+ alpha implies alpha=60%`