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Rate constant for the reaction NO2+COtoN...

Rate constant for the reaction `NO_2+COtoNO+CO_2` are `1.3M^(-1)S^(-1)` at 700 K and `23 M^(-1)S^(-1)` at 800 K. What will be the rate constant at 750 K ? (`ln23/1.3=2.873, e^(1.53)=4.629,e^(1.34)=3.822`)

A

`12.15 M^(-1) S^(-1)`

B

`24.3 M^(-1) S^(-1)`

C

`6.0 M^(-1) S^(-1)`

D

`20.0 M^(-1) S^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C

`"ln"23/1.3=(Ea)/R(1/700-1/800)`
`implies (Ea)/R="ln"23/1.3xx(700xx800)/100`
then , `"ln"k_(750)/1.3="ln"23/1.3xx(700xx800)/100(1/700-1/750)`
`"ln"k_(750)/1.3=2.873xx5600xx50/(700xx750)implies "ln"k_(750)/1.3=1.532`
`implies k_(750)=1.3xx4.629=6 M^(-1) s^(-1)`
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