If `vec A= 3i + j +2k` and `vec B = 2i - 2j +4k` and `theta` is the angle between the two vectors, then `sin theta` is equal to

If theta is the angle between the vectors 2i-2j+4k and 3i+j+2k then sin theta =

if theta angle between two vectors 2i+j+7k and i+5j+k then cos theta

If theta is th angle between the vector 2i - 2j + 4k and 3i + j + 2k, then sin theta =

Find the angle between two vectors vec(A)=2i+j-k and vec(B)=i-k .

The vector vec a and vec b satisfy the equation 2vec a+vec b=vec p and +2vec b=vec q ,where vec p=hat i+hat j and vec q=hat i-vec j If theta is the angle between vec a and vec b backslash ,then cos theta=(4)/(5) b.sin theta=(1)/(sqrt(2))c*cos theta=-(4)/(5)d*cos theta=-(3)/(5)

If theta is the angle between vec a = 2i-j+k and vec b = i+2j+k , then cos theta=

If vec(A) = 2 I + j - k , vec(B) = I + 2 j + 3 k , and vec(C ) = 6 i - 2 j - 6 k ,then the angle between (vec(A) + vec(B)) and vec(C ) will be