If a die is thrown 5 times, then find the probability that an odd number will come up exactly three times.

Explanation

Here, n=5,p=`(1/6+1/6+1/6)=1/2 and q=1-p=1-1/2=1/2`
Also, r=3
`thereforeP(X=r)=""^(n)C_(r)(p)^(r )(q)^(n-r)=""^(5)C_(3)(1/2)^(3)(1/2)^(5-3)`
`=(5!)/(3!2!)cdot1/8cdot1/4=10/32=5/16`