The probability distribution of a random variable x is given as under
`P(X=x)={{:(kx^(2),x="1,2,3"),(2kx,x="4,5,6"),("0,","otherwise"):}`
where, k is a constant. Calculate
(i) E(X) (ii) `E(3X^(2))` (iii) `P(Xge4)`

Explanation

To solve the problem, we will follow these steps:

### Step 1: Determine the value of k

The probability distribution is given as:
- For \( x = 1, 2, 3 \): \( P(X=x) = kx^2 \)
- For \( x = 4, 5, 6 \): \( P(X=x) = 2kx \)
- For all other values: \( P(X=x) = 0 \)
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