If A and B are suchg that events that `P(A)gt0andP(B)ne1`, then `P(A'//B')` equals to

Options

A. 1-P(A/B)
B. 1-P(A'/B)
C. `(1-P(AcupB))/(P(B'))`
D. P(A')/P(B')

Explanation

`therefore P(A)gt0andP(B)ne1`
`P(A'//B')=(P(A'capB'))/(P(B'))=(1-P(AcupB))/(P(B'))`