A bag containing 5 red and 3 blue balls. If 3 balls are drawn at random without replacement the probability that exactly two of the three balls were red, the first being red is

Options

A. `1/3`
B. `4/7`
C. `15/28`
D. `5/28`

Explanation

Let `E_(1)`=Event that first ball being red
and `E_(2)`= Event that exactly tw of the three balls being red
`therefore P_(E_(1))=P_(R)cdotP_(R)cdotP_(R)+P_(R)cdotP_(R)cdotP_(barR)+P_(R)cdotP_(barR)cdotP_(R)+P_(R)cdotP_(barR)cdotP_(barR)`