If a die is thrown and a card is selected at random from a deck of playing cards, than the probability of getting an even number on the die and a spade card is

Options

A. `1/2`
B. `1/4`
C. `1/8`
D. `3/4`

Explanation

Let `E_(1)`=Event for getting an even number on the die
and `E_(2)`=Event that a spade card is selected
`thereforeP(E_(1))=3/6=1/2andP(E_(2))=13/52=1/4`
Then, `P(E_(1)capE_(2))=P(E_(1))cdotP(E_(2))=1/2cdot1/4=1/8`