A box contains 3 orange balls, 3 green balls and 2 blue balls. Three balls are drawn at random from the box without replacement. The probability of drawing 2 green balls an one blue ball is

Options

A. `3/28`
B. `2/21`
C. `1/28`
D. `167/168`

Explanation

Probability of drawing 2 green balls and one blue ball
`=P_(G)cdotP_(G)cdotP_(B)+P_(B)cdotP_(G)cdotP_(G)+P_(G)cdotP_(B)cdotP_(G)`
`=3/8cdot2/7cdot2/6+2/8cdot3/7cdot2/6+3/8cdot2/7cdot2/6`
`=1/28+1/28+1/28=3/28`