Two dice are thrown. If it is known that the sum of numbers on the dice was less than 6, the probability of getting a sum 3, is

Options

A. `1/18`
B. `5/18`
C. `1/5`
D. `2/5`

Explanation

Let `E_(1)`=Event that the sum of numbers on the dice was less than 6
and `E_(2)`=Event that the sum of numbers on the dice is 3
`thereforeE_(1)`={(1/4),(4,1),(2,3),(3,2),(2,2),(1,3),(3,1),(1,2),(2,1),(1,1)}
`rArrn(E_(1))=10`
and `E_(2)`={(1,2),(2,1)}`rArrn(E_(2))=2`
`therefore` Required probability`=2/10=1/5`