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Let A and B be two events. If P(A/B)=P(A...

Let A and B be two events. If P(A/B)=P(A), then A is …. of B

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`becauseP(A//B)=(P(AcapB))/(P(B))`
`rArrP(A)=(P(AcapB))/(P(B))`
`rArrP(A)cdotP(B)=P(AcapB)`
So, A is independent of B.
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