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Calculate the area under the curve y=2sq...

Calculate the area under the curve `y=2sqrtx` included between the lines x = 0 and x = 1.

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The correct Answer is:
N/a
We have, `y=2sqrtx,x=0" and "x=1`

`:. "Area of shaded region," A =int_(0)^(1)(2sqrt2)dx`
`=2.[(x^(3//2))/3 .2]_(0)^(1)`
`=2(2/3 .1-0)=4/3" sq units"`
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