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Area of the regionbounded by the curve y...

Area of the regionbounded by the curve y =cos xbetween x = 0 and `x=pi` is

A

`2" sq units"`

B

`4" sq units"`

C

`3" sq units"`

D

`1" sq unit"`

Text Solution

Verified by Experts

The correct Answer is:
A

Required area enclosed by the curve `y=cosx, x=0" and " x=pi` is

`A=int_(0)^(pi//2)cosx dx +abs(int_(pi//2)^(pi)cosxdx)
`=[sin.pi/2-sin0]+abs(sin.pi/2-sinpi)`
`=1+1=2" sq units"`
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