59 g of an amide obtained from a carboxylic cid, RCOOH, upon heating with alkali liberated, 17 g of ammonia. The acid is '

Options

A. ) Formic acid
B. Acetic acid
C. Propionic acid
D. Benzoic acid.

Answer

B

Explanation

`RCOHH_(2)+NaOH rarr RCOOH +NH_(3)`
As 1 mole of `NH_(3)` is given by one mole of amide.
Thus mol.mass of `RCONH_(2)` is
A+12+16+14+2
A +44=59
A=59-44=15
Hence alkyl grorup with mol.mass A=15 is `CH_(3)`.Thus acid is `CH_(3)COOH`