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An organic compound with C =40 % and H= ...

An organic compound with C =40 % and H= 13.33 % and N=46.67 % Its empirical empirical formula would be

A

CHN

B

`C_(2)H_(2)N`

C

`CH_(4)N`

D

`C_(3)H_(7)N`

Text Solution

Verified by Experts

The correct Answer is:
C
Ratio of C:H:N
`=(40)/(12):(13.33)/(1)=(46.67)/(14)=1:4:1`
Empirical formula `=CH_2O`
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DINESH PUBLICATION-PURIFICATION & CHARACTERISATION OF ORGANIC COMPOUND -Revision Q.F.Competitive exams
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  2. An organic compound with C =40 % and H= 6.7% will have the empirical f...

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  3. An organic compound with C =40 % and H= 13.33 % and N=46.67 % Its empi...

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  4. Empirical formula of compound is CH(2)O.If its molecular weight is 180...

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  5. The Beilstein test for organic compounds is used to detect

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  7. Which of the following has molecular weight of 92 ?

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  14. If 0.765 g of an acid gives 0.535 g of CO(2) and 0.138 g of H(2)O, the...

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  16. In a hydrocarbon, mass ratio of hydrogen and carbon is 1 : 3, the empi...

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  17. The empirical formula of a compound is CH2 . One mole of compound has ...

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  19. In a compound C, H, N atoms are present in 9:1:3.5 by weight. Molecula...

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