An organic compound containing carbon hydrogen and oxygen contains 52 .2 % carbon and 13.04 % hydrogen .Vapour density of the compound is 23 .Its molecular formula will be

Options

A. `C_(2)H_(6)O`
B. `C_(3)H_(6)O`
C. `C_(4)H_(8)O`
D. `C_(5)H_(10)O`

Answer

A

Explanation

Precentage of O=100-(52.2+13.04)=34.76
Ratio of atoms
C:H:O`=(52.2)/(12):(13.04)/(1):(34.76)/(16)`
`=4.35:13:04:2.17=2:6:1.`
E.F`=C_2H_6O`
E.F mass `=2xx12+6xx1+1xx16=46`
Mol.mass `=2xxV.D=2xx23=46`
`n=("Mol.mass")/("E.F mass")=46/46=1`
`therefore MF=(E.F.)_(n)=(C_2H_6O)_(1)=C_2H_6O`