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An organic compound on analysis gave C=3...

An organic compound on analysis gave C=39.9 % ,H= 6.7 % and O =53.4 % .The empricial formula of the compound is

A

`CHO_2`

B

`CH_2O`

C

`C_2H_2O_2`

D

CHO

Text Solution

Verified by Experts

The correct Answer is:
B
`C=(39.9)/(12)=3.35,H=(6.7)/(1)=6.7,`
O=(53.4)/(16)=3.34`
`therefore E.F = CH_(2)O`
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