Home
Class 12
CHEMISTRY
A gaseous hydrocarbon with empirical for...

A gaseous hydrocarbon with empirical formula `CH_(2)` has a density of 12.5 g `gL^(-1)` at N.T.P The molecular formula of the compound is

A

`C_2H_2`

B

`C_6H_6`

C

`C_2H_4`

D

`C_3H_6`

Text Solution

Verified by Experts

The correct Answer is:
C

22.4 L of a gas/ vapour at N.T.P has a mass of 1.25 g .
22.4 L of the gas at NTP has a mass of
`=1.25 xx 22.4 g = 28 g `
`therefore` Mol mass of hydrocarbon =28
`there " Hydrocarbon " =C_2H_4`
Promotional Banner

Topper's Solved these Questions

  • PURIFICATION & CHARACTERISATION OF ORGANIC COMPOUND

    DINESH PUBLICATION|Exercise REASON ASSERTION TYPE MCQ|10 Videos
  • PRINCIPLES RELATED TO PRACTICAL CHEMISTRY

    DINESH PUBLICATION|Exercise Brain teasers-42|1 Videos
  • REDOX REACTIONS

    DINESH PUBLICATION|Exercise Ultimate Preparation|9 Videos

Similar Questions

Explore conceptually related problems

The empirical formula of compound is CH_(2)O .Its vapour density is 60 . The molecular formula of the compound is

The empirical formula of a compound is CH_2O and its vapour density is 30. The molecular formula of the compound is:

The empirical formula of an organic compound is CH_(2)O . Its vapour density is 45. The molecular formula of the compound is

A compound having empirical formula (C_3H_4O)n has vapour density 84. The molecular formula of this compound is

A compound having the empirical formula (C_(3)H_(4)O)_(n) has a molar mass of 170 +- 5 . The molecular formula of this compound is

Empirical formula of a compound is CH_(2)O and its vapour density is 30. Molecular formula of the compound is