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A purified pepsin was subjected to amino...

A purified pepsin was subjected to amino acid analysis. The amino acid present in smallest amount was lysine, `C_(6)H_(14)N_(2)O_(2)` and the amount of lysine was found to be 0.43 g per 100 g of protein. The minimum molecular mass of protein is

A

34000

B

14600

C

43000

D

None to these.

Text Solution

Verified by Experts

The correct Answer is:
A
Mol. Mass of lysine `(C_6H_(14)N_2O_2)`=146
Min.mol. Mass `=(100 xx "Mol . Mass of lysine")/("% of lysine in the pepsin")`
`(100xx146)/(0.43)=(1460000)/(43)`= 340000 (approx)
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