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XeF(6)+PF(5) to...

`XeF_(6)+PF_(5) to `

A

`XeF_(6)`

B

`[XeF]^(+)[PF_(6)]^(-)`

C

`XeF_(4)`

D

`[PF_(4)]^(+)[XeF_(3)]^(-)`

Text Solution

Verified by Experts

The correct Answer is:
B

`PF_(5)` is a fluoride ion acceptor so it yields cationic species with xenon fluorides.
`XeF_(2) + PF_(5) rarr [XeF]^(+)[PF_(6)]^(-)`
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