Hybridization and shape of `XeF_(4)` is

Options

A. `sp^(3)d`, trigonal bipyramidal
B. `sp^(3)`, tetrahedral
C. `sp^(3)d^(2)`, square planar
D. `sp^(3)d^(2)`, hexagonal.

Answer

C

Explanation

In `XeF_(4)`
No. of electrons around Xe = 8 + 4 = 12
No. of electrons pairs = 12/2 = 6
Hybridisation = `sp^(3)d^(2)`
Bond pairs = 4
Lone pairs = 6 - 4 = 2
Therefore, `XeF_(4)` is square planar.