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The circumference of a circular garder is 572 m. Outside the garden a road of width 3.5 m runs around it. Calculate the cost of repairing the road at the rate of Rs 3.75 per square metre

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To solve the problem step by step, we will follow these instructions: ### Step 1: Calculate the radius of the circular garden. The formula for the circumference \( C \) of a circle is given by: \[ C = 2\pi r \] where \( r \) is the radius. Given that the circumference of the garden is 572 m, we can rearrange the formula to find the radius: \[ r = \frac{C}{2\pi} = \frac{572}{2\pi} \] ### Step 2: Substitute the value of \( \pi \). Using \( \pi \approx 3.14 \): \[ r = \frac{572}{2 \times 3.14} = \frac{572}{6.28} \approx 91.1 \text{ m} \] ### Step 3: Calculate the outer radius of the road. The road runs around the garden with a width of 3.5 m. Therefore, the outer radius \( R \) is: \[ R = r + 3.5 = 91.1 + 3.5 = 94.6 \text{ m} \] ### Step 4: Calculate the area of the circular garden. The area \( A \) of a circle is given by: \[ A = \pi r^2 \] Substituting the radius of the garden: \[ A_{garden} = \pi (91.1)^2 \] ### Step 5: Calculate the area of the larger circle (garden + road). Using the outer radius: \[ A_{outer} = \pi (94.6)^2 \] ### Step 6: Calculate the area of the road. The area of the road is the difference between the area of the outer circle and the area of the garden: \[ A_{road} = A_{outer} - A_{garden} \] ### Step 7: Calculate the cost of repairing the road. The cost of repairing the road is given by the area of the road multiplied by the cost per square meter: \[ \text{Cost} = A_{road} \times 3.75 \] ### Step 8: Substitute the values and calculate. Now, let's perform the calculations step by step. 1. Calculate \( A_{garden} \): \[ A_{garden} = \pi (91.1)^2 \approx 3.14 \times 8294.21 \approx 26000.14 \text{ m}^2 \] 2. Calculate \( A_{outer} \): \[ A_{outer} = \pi (94.6)^2 \approx 3.14 \times 8962.76 \approx 28100.14 \text{ m}^2 \] 3. Calculate \( A_{road} \): \[ A_{road} = 28100.14 - 26000.14 \approx 2100 \text{ m}^2 \] 4. Calculate the cost: \[ \text{Cost} = 2100 \times 3.75 \approx 7875 \text{ Rs} \] ### Final Answer: The cost of repairing the road is approximately Rs 7875. ---
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NAGEEN PRAKASHAN-AREA RELATED TO CIRCLES-Exercise 12 A
  1. The diameter of a circular plot is 49m. Find the cost of fencing it at...

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  2. Two circles touch internally. The sum of their areas is 116 pi cm^(2) ...

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  3. The circumference of a circular garder is 572 m. Outside the garden a ...

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  4. A field is in the form of a circle. A fence is to be erected around...

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  5. The sum of the radii of two different circles is 18.5 cm and the diffe...

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  6. A race track is in the form of a ring whose outer and inner circumfere...

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  7. The area enclosed by the circumference of two concentric circles is 42...

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  8. Find the circumference of the circle whose area is 16 times the area o...

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  9. Calculate the circumference of a circle whose area is equal to the sum...

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  10. The diameters of two given circles are in the ratio 3 : 4 and the sum ...

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  11. The number denoted by the area of a cicle is five times the number den...

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  12. A park is in the form of a circle with radius 35m. At the centre of th...

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  13. If a square is inscribed in a circle, find the ratio of the areas of ...

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  14. Area of a circle is 61m^(2). Find the area of the greatest square cons...

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  15. The area of a circle inscribed in an equilateral triangle is 154\ c...

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  16. Prove that the area of a circular path of uniform width h surroundi...

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  17. The radius of a wheel is 77 cm, find the number of revolutions it will...

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  18. If the wheel of a bus with 50 cm radius makes 280 revolutions per minu...

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  19. A man runs with a speed of 15.84 km/hr. He completes 12 rouds of a cir...

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  20. A bucket is raised from a well by means of a rope which is wound round...

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