Peter throws two different dice together and finds the product of the two numbers obtained. Rina throws a die and squares the number obtained. Who has the better chance to get the number 25?

Explanation

For Peter : n(s) = 36
Let A be the event of getting 'product of two numbers is 25".
`therefore` Favourable cases are (5,5)
`therefore" "n(A)=1`
`therefore" "P(A)=(n(A))/(n(S))=(1)/(36)" ...(1)"`
For Rina : n(S)=6
Let B be the event of getting 'a number whose square is 25''.
`therefore` Favourable cases are 5.
`therefore" "n(B)=1`
`therefore" "P(B)=(n(n(B))/(n(S))=(1)/(6)" ...(2)"`
From equations (1) and (2), we see that
`P(B)gtP(A)`
`i.e.," "Probability of Bgt Probability of A`
Hence, Rina has better chances to get the number 25.