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Two dice are numbered 1,2,3,4,5,6 and 1,...

Two dice are numbered 1,2,3,4,5,6 and 1,1,2,2,3,3 respectively. They are thrown and the sum of the numbrees of them is noted. Find the probability of getting each sum from 2 to 9 separately.

Text Solution

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Total number of all possible outcomes, i.e., T(E) = 36
(i)Number of favourable outcome when
Sum of numbers on two dice is 2, i.e., (1,1),(1,1),
`therefore" "F(E) = 2 `
`rArr " "P_(1)(E)= (F(E))/(T(E)) = (2)/(36) = (1)/(18)`
(ii) Number of favourable outcomes when
Sum of number on two dice is 3, i.e., (1,2),(1,2),(2,1),(2,1)
`therefore " "F(E) = 4`
`rArr " "P_(2)(E) = (F(E))/(T(E)) = (4)/(36) =(1)/(9)`
(iii) Number of favourable outcomes when
Sum of number on two dice is 4, i.e., (1,3),(1,3),(2,2),(2,2),(3,1),(3,1).
`therefore" "F(E) = 6`
`rArr " "P_(3) (E) = (F(E))/(T(E)) = (6)/(36) = (1)/(6)`
(iv) Number of favourable outcomes when
Sum of numbers on the dice is 5,i.e, (2,3),(2,3),(3,2),(3,2),(4,1),(4,1)
`therefore " "F(E) = 6`
` rArr " "P_(4) (E) = (F(E))/(T(E)) = (6)/(36) =(1)/(6)`
(v) Number of favourable outcomes when
Sum of numbers on two dice is 6,i.e., (3,3),(3,3),(4,2),(4,2),(5,1),(5,1).
`therefore " "F(E) = 6`
` rArr " "P_(5) (E) = (F(E))/(T(E)) = (6)/(36) =(1)/(6)`
(vi) Number of favourable outcomes when
Sum of numbers on two dice is 7, i.e, (4,3),(4,3),(6,1),(6,1),(5,2) ,(5,2)`
`therefore " "F(E) = 6`
` rArr " "P_(6 ) (E) = (F(E))/(T(E)) = (6)/(36) =(1)/(6)`
(vii) Number of favourable outcomes when
Sum of numbers on two dice is 8 ,i.e., (5,3),(5,3),(6,2),(6 ,2).
`therefore " "F(E) = 6`
` rArr " "P_(7 ) (E) = (F(E))/(T(E)) = (6)/(36) =(1)/(6)`
(viii)Number of favourable outcoes when
Sum of numbers on both dice is 9 .i.e., (6,3),(6,3)
`therefore " "F(E) = 2`
`rArr " "P_(8)(E)=(F(E))/(T(E)) = (2)/(36) = (1)/(8)`
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