given that `tan(theta_1 + theta_2) = (tantheta_1 + tantheta_2)/(1-tantheta_1*tantheta_2)` find `(theta_1+theta_2)` when `tantheta_1 =1/2 , tantheta_2=1/3`

Explanation

`tan(theta_(1)+theta_(2))=(tantheta_(1)+tantheta_(2))/(1-tantheta_(1)*tantheta_(2))= (1/(2)+(1)/(3))/(1-(1)/(2)xx(1)/(3))=((3+2)/6)/(1-(1)/(6))=((5)/6)/(5/(6))=1=tan45^(@)`
`rArr theta_(1)+theta_(2)=45^(@)`