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(1+secA)/secA=(sin^2A)/(1-cosA)...

`(1+secA)/secA=(sin^2A)/(1-cosA)`

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L.H.S. `=(1+secA)/(secA)=(1+(1)/(cosA))/(1/(cosA))=((cosA+1)/(cosA))/(1/(cosA))=(1+cosA)/(1)`
`=(1+cosA)/(1)xx(1-cosA)/(1-cosA)=(1-cos^(2)A)/(1-cosA)=(sin^(2)A)/(1-cosA)=R.H.S.`
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