Home
Class 10
MATHS
Evaluate : (i)tan42^(@)-cot48^(@)...

Evaluate :
(i)`tan42^(@)-cot48^(@)`
(ii)`sec36^(@)-"cosec"54^(@)`

Text Solution

Verified by Experts

(i) `tan42^(@)-cot48^(@)=tan42^(@)-cot(90^(@)-42^(@))`
(ii) `sec36^(@)-"cosec " 54^(@)=sec36^(@)-"cosec"(90^(@)=36^(@))`
`=sec36^(@)-sec36^(@)=0`
Promotional Banner

Topper's Solved these Questions

  • INTRODUCTION TO TRIGONOMETRY

    NAGEEN PRAKASHAN|Exercise Problems From NCERT/exemplar|29 Videos

  • INTRODUCTION TO TRIGONOMETRY

    NAGEEN PRAKASHAN|Exercise Exercise 8a|20 Videos

  • CONSTRUCTIONS

    NAGEEN PRAKASHAN|Exercise PROBLEMS FROM NCERT/ EXEMPLAR|10 Videos

  • LINEAR EQUATIONS IN TWO VARIABLES

    NAGEEN PRAKASHAN|Exercise Revision Exercise Long Answer Questions|8 Videos

Similar Questions

Explore conceptually related problems

Without using trigonometric tables , evaluate : (i) (sin11^(@))/(cos79^(@)) (ii) (sec15^(@))/("cosec"75^(@)) (iii) (tan54^(@))/(cot36^(@)) (iv) (cos68^(@))/(sin22^(@)) (v) ("cosec"24^(@))/(sec66^(@)) (vi) (cot18^(@))/(tan72^(@))

Evaluate the following : (i) (sin58^(@))/(cos32^(@)) (ii) (sec42^(@))/("cosec"48^(@)) (iii) (tan37^(@))/(cot53^(@))

Without using trigonometric tables , prove that : (i) sin50^(@)-cos40^(@)=0 (ii) tan36^(@)-cot54^(@)=0 (iii) sec25^(@)-"cosec "65^(@)=0 (iv) sin^(2)32^(@)+sin^(2)58^(@)=1 (v) "cosec"^(2)39^(@)tan^(2)51^(@)=1 (vi) sec^(2)10^(@)-cot^(2)80^(@)=1

Evaluate : (sin 30^(@) + tan45^(@) - cosec 60^(@))/(sec 30^(@) + cos 60^(@) + cot 45^(@))

Without using trigonometric tables, evaluate : (i) (sin16^@)/(cos 74^@) (ii) (sec 11^@)/(cosec 79^@) (iii) (tan 27^@)/(cot 63^@) (iv) (cos 35^@)/(sin 55^@) (v) (cosec 42^@)/(sec 48^@) (vi) (cot 38^@)/(tan 52^@)

Without using trigonometric tables, evaluate : (i) (cos 53^@)/(sin 37^@) (ii) (tan68^@)/(cot 22^@) (iii) (sec49^@)/(cosec 41^@) (iv) (sin 30^@17')/(cos 59^@43')

Without using trigonometric tables , evaluate : (i) (sin40^(@))/(cos50^(@))+(3tan50^(@))/(cot40^(@)) (ii) (sec37^(@))/("cosec "53^(@))-(tan20^(@))/(cot70^(@)) (iii) (cos74^(@))/(sin16^(@))+(sin12^(@))/(cos78^(@))-sin18^(@)sec72^(@) (iv) sin35^(@)sec55^(@)+(4sec32^(@))/("cosec "58^(@))