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Without using trigonometric table, evaluate the following: `(cosec^2(90-theta)-tan^2theta)/(4(cos^2 48^@+cos^2 42^@))-(2tan^2 30^@ sec^2 52^@ sin^2 38^@)/(cosec^2 70^@-tan^2 20^@`

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`("cosec"^(2)(90^(@)-theta)-tan^(2)theta)/(4(cos^(2)48^(@)+cos^(2)42^(@)))-(2tan^(2)30^(@)sec^(2)52^(@)sin^(2)38^(@))/(("cosec"^(2)70^(@)-tan^(2)20^(@)))`
`=(sec^(2)theta-tan^(2)theta)/(4{cos^(2)(90^(@)-42^(@))+cos^(2)42^(@)})-(2((1)/(sqrt(3)))^(2)sec^(2)(90^(@)-38^(@))sin^(2)38^(@))/("cosec"^(2)(90^(@)-20^(@))-tan^(2)20^(@))`
`=(1)/(4(sin^(2)42^(@)+cos^(2)42^(@)))-(2"cosec"^(2)38^(@)*sin^(2)38^(@))/(3{sec^(2)20^(@)-tan^(2)20^(@)})`
`=(1)/(4)-(2"cosec"^(2)38^(@)xx((1))/("cosec"^(2)38^(@)))/(3)=(1)/(4)-(2)/(3)=(-5)/(12)`
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