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If sin36^(@)=p , then find sin 54^(@) in...

If `sin36^(@)=p` , then find sin `54^(@)` in terms of p.

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We have ,
`sin36^(@)=p`
`rArrsin^(2)36^(@)=p^(2)rArr1-cos^(2)36^(@)=p^(2)`
`rArrcos^(2)36^(@)=1-p^(2)rArrcos^(2)(90^(@)-54^(@))=1-p^(2)`
`rArrsin^(2)54^(@)=1=p^(2)`
`rArrsin54^(@)=sqrt(1-p^(2))` (taking only positive sign as `54^(@)` lies in I quadrant)
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