If `tan(A+B)=sqrt(3)` and `t a n(A B)=1/(sqrt(3));` `0o B ,` find A and B.

Explanation

`tan(A+B)=sqrt(3)`
`rArrtan(A+B)=tan60^(@)rArrA+B=60^(@)` . . . (1)
and `tan(A-B)=(1)/(sqrt(3))`
`rArrtan(A-B)=tan30^(@)rArrA-B=30^(@)` . . .(2)
Adding equations (1) and (2), we get
`A+B=60^(@)`
`(A-B=30^(@))/(2A=90^(@))`
`rArrA=45^(@)`
Put `A=45^(@)` in equation (1) we, get
`45^(@)+B=60^(@)rArrB=15^(@)`
`:. A=45^(@)andB=15^(@)`