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sin^(2)5^@+sin^(2)10^@+sin^(2)15^@ +.......

`sin^(2)5^@+sin^(2)10^@+sin^(2)15^@ +.......+sin^(2)85^@ + sin^(2)90^@=`

Text Solution

Verified by Experts

The correct Answer is:
`(19)/(2)`
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