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Using the formula cos A =sqrt((1+cos2A)/...

Using the formula cos A `=sqrt((1+cos2A)/(2))`, find the value of `cos30^(@)`, it is given that `cos60^(@)=(1)/(2)`.

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To find the value of \( \cos 30^\circ \) using the formula \( \cos A = \sqrt{\frac{1 + \cos 2A}{2}} \), we will follow these steps: ### Step 1: Identify \( A \) and \( 2A \) Let \( A = 30^\circ \). Then, \( 2A = 60^\circ \). ### Step 2: Use the given value of \( \cos 60^\circ \) We know that \( \cos 60^\circ = \frac{1}{2} \). ### Step 3: Substitute into the formula Now, substitute \( A = 30^\circ \) into the formula: \[ \cos 30^\circ = \sqrt{\frac{1 + \cos 60^\circ}{2}} \] ### Step 4: Substitute the value of \( \cos 60^\circ \) Replace \( \cos 60^\circ \) with \( \frac{1}{2} \): \[ \cos 30^\circ = \sqrt{\frac{1 + \frac{1}{2}}{2}} \] ### Step 5: Simplify the expression First, simplify the numerator: \[ 1 + \frac{1}{2} = \frac{2}{2} + \frac{1}{2} = \frac{3}{2} \] Now substitute this back: \[ \cos 30^\circ = \sqrt{\frac{\frac{3}{2}}{2}} = \sqrt{\frac{3}{2} \cdot \frac{1}{2}} = \sqrt{\frac{3}{4}} \] ### Step 6: Final simplification Now, simplify \( \sqrt{\frac{3}{4}} \): \[ \cos 30^\circ = \frac{\sqrt{3}}{2} \] Thus, the value of \( \cos 30^\circ \) is \( \frac{\sqrt{3}}{2} \). ---
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NAGEEN PRAKASHAN-INTRODUCTION TO TRIGONOMETRY-Revision Exercise Short Answer Questions
  1. If A=30^(@),verify that cos2A=cos^(2)A-sin^(2)A.

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  2. if A= 45^o then verify sin2A=2sinAcosA , cos2A=1-sin^2A

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  3. Using the formula cos A =sqrt((1+cos2A)/(2)), find the value of cos30^...

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  4. In the adjoining figure , DeltaABC is a right - angled triangle , righ...

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  5. If sin(A-B)=1/2,""""cos(A+B)=1/2, 0o<A+Blt=90o,""""A > B , find A and ...

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  6. Find the value of sin30^(@) geometrically.

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  7. Find the value of sin60^(@) geometrically.

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  8. Prove that sqrt(sec^(2)theta + cosec^(2)theta) = tantheta + cottheta.

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  9. Prove that : sqrt((1+costheta)/(1-costheta))="cosec"theta+cottheta

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  10. sqrt((1+sintheta)/(1-sintheta))+sqrt((1-sintheta)/(1+sintheta)) is equ...

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  11. Prove that : tan^(2)theta-sin^(2)theta=tan^(2)thetasin^(2)theta

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  12. Prove that : (tanA+sinA)/(tanA-sinA)=(secA+1)/(secA-1)

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  13. Prove that : sin^(2)Acos^(2)B-cos^(2)Asin^(2)B=sin^(2)A-sin^(2)B

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  14. Prove that : sin^(2)theta+cos^(4)theta=cos^(2)theta+sin^(4)theta

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  15. Prove that : sin^(2)theta+(1)/(1+tan^(2)theta)=1

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  16. Prove that : (1-costheta)(1+costheta)(1+cot^(2)theta)=1

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  17. Prove that : (tan^(2)theta)/(1+tan^(2)theta)+(cot^(2)theta)/(1+cot^...

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  18. If tan3A=cot(A-10^(@)) where 3A is an angle , find A.

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  19. If cos5A=sin(A-30^(@)) where 5A is an acute angle , find A.

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  20. Show that : (cot(90^(@)-theta)*sin(90^(@)-theta))/(sintheta)+(cot50^...

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