Home
Class 10
MATHS
Find the area of triangle, whose vertice...

Find the area of triangle, whose vertices are (2,3), (7,5) and (-7,-5).

Text Solution

Verified by Experts

Area of triangle `=1/2[x_(1)(y_(2)-y_(3))+x_(2)(y_(3)-y_(1))+x_(2)(y_(3)-y_(1))+x_(3)(y_(1)-y_(2))`
`=1/2[2(5+5)+7(-5-3)-7(3-5)]=1/2(20-56+14)=-11`
But the area of triangle connot be negative
`therefore` Area of triangle = 11 square units
Promotional Banner

Topper's Solved these Questions

  • CO-ORDINATE GEOMETRY

    NAGEEN PRAKASHAN|Exercise Miscellaneous Examples|8 Videos

  • CO-ORDINATE GEOMETRY

    NAGEEN PRAKASHAN|Exercise Problems Of NCERT/exemplar|14 Videos

  • CIRCLES

    NAGEEN PRAKASHAN|Exercise Revision Exercise Long Answer Questions|3 Videos

  • CONSTRUCTIONS

    NAGEEN PRAKASHAN|Exercise PROBLEMS FROM NCERT/ EXEMPLAR|10 Videos

Similar Questions

Explore conceptually related problems

Find the area of the triangle, whose vertices are (2,1), (4,5) and (6,3).

Find the area of triangle whose vertices are (2,7), (1,1) and (10,8).

Find the area of a triangle whose vertices are (1,-1),(-4,6) and (-3,-5)

Find the area of triangle whose vertices are A(6,7),B(2,-9) and C(-4,1)

Using determinants, find the area of the triangle whose vertices are (1, 4), (2, 3) and (-5, -3). Are the given points collinear?

Find the area of the triangle whose vertices are (-3,1),(2,4) and (5,1).

Find the area of the triangle whose vertices are (3,8), (-4,2) and (5,1)

Find the area of the triangle whose vertices are (3,8), (-4,2) and (5,1)

Find the area of the triangle whose vertices are (3,8), (-4,2) and (5, -1).