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Find the area of the triangle, whose ver...

Find the area of the triangle, whose vertices are (a,c+a), (a,c) and (-a,c-a).

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Area of triangle `=1/2[x_(1)(y_(2)-y_(3))+x_(2)(y_(3)-y_(1))+x_(3)(y_(3)-y_(1))+x_(3)(y_(1)-y_(2))]`
`=1/2[a(c-c+a)+a(c-a-a)-a(c+a-c)]`
`=1/2[a^(2)-2a^(2)-a^(2)]=-a^(2)`
But area of triangle connot be negative
`therefore` Area of triangle `=a^(2)` square units
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