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The 17^(t h) term of an AP exceeds its 1...

The `17^(t h)` term of an AP exceeds its `10^(t h)` term by 7. Find the common difference.

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Let the first term and the common difference of the A.P. be 'a' and 'd' respectively.
Given that, `a_(17)=a_(10)+7`
`rArr a_(17)-a_(10)=7`
`rArr {a+(17-1)d}-{a+(10-1)d}=7`
`rArr (a+16d)-(a+9d)=7`
`rArr a+16d-a-9d=7`
`rArr 7d=7 rArr d=1`
`:.` Common difference =1.
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