The ratio of the 11th term to the 18th term of an AP is `2:3`. Find the ratio of the 5th term to the 21st term and also the ratio of the sum of the first five terms to the sum of the first 21 terms.

Explanation

Let'a' and 'd' be the first term and common difference respectively of the A.P.
Given that, `(a_(11))/(a_(18))=(2)/(3)`
`rArr (a+10d)/(a+17d)=(2)/(3)`
`rArr 3a+30d=2a+34d`
`a=4d " " ...(1)`
Now, `(a_(5))/(a_(21))=(a+4d)/(a+20d) " " `[from (1)]
`=(4d+4d)/(4d+20d)`
`=(8d)/(24d)=(1)/(3)=1:3`
and `(S_(5))/(S_(21))=((5)/(2)(2a+4d))/((21)/(2)(2a+20d))=(5(a+2d))/(21(a+10d)) " " `[from (1)]
`=(5(6d))/(21(14d))=(5)/(49)=5:49`